[5 points] Prove the characteristic parallelogram property for wave equations.
[5 points] Solve the problem with two different characteristic speedsc1andc2:
(∂t∂−c1∂x∂)(∂t∂−c2∂x∂)u=0,in R×(0,∞).Analyze the casesc1=c2andc1=c2, and derive D’Alembert’s formula as a special case. Discuss any potential loss of regularity in the one-dimensional case.
[5 points] Integrate the wave equationutt−uxx=f(x,t)in the characteristic triangleP(x,t),Q(x−ct,0),R(x+ct,0)to derive a formula for the solution. (Hint: Use the identityutt−uxx=(ut)t−(ux)x.)
[5 points] Solve the wave equation in the first quadrant with non-homogeneous Dirichlet boundary condition:
utt−uxx=0,in (0,∞)×(0,∞)with initial and boundary conditions:
u(x,0)=f(x),ut(x,0)=g(x),u(0,t)=h(t),t>0.Derive the formula forx<ctusing the parallelogram identity.
[5 points] Solve the above equation with the Neumann non-homogeneous boundary condition whereu(0,t)=h(t)is replaced byux(0,t)=h(t).
[5 points] Letc1,…,ckbe distinct positive real numbers. Show that the solution of the equation:
(∂t2−c12∂x2)…(∂t2−ck2∂x2)u=0,can be written as:
u(x,t)=j=0∑kuj(x,t),where eachujsatisfies∂t2uj−cj2∂x2uj=0. This result also holds in higher dimensions.
[5 points] Consider the casen=3for:
(∂t2−c2∂x2)(∂t2−c2∂x2)u=0,c>0.Given smooth initial data∂tju(x,0)=fj(x)forj=0,1,2,3, explicitly determine the solution.
[5 points] Consider the wave equation:utt−Δu=0,in Rn×(0,∞),with initial data:u(x,0)=ϕ(x),ut(x,0)=ψ(x).Verify that the solution is given by:u(x,t)=uϕ(x,t)+∫0tuψ(x,s)ds,and also by:u(x,t)=vψ(x,t)+∂t∂vϕ(x,t).